Last Chance to Raise Objections on CSIR UGC NET 2024 Answer Key – Submit by Today

The National Testing Agency (NTA) will close the provisional answer key objection window for the Joint CSIR-UGC NET 2024 today, August 11, at 11:50 PM. Candidates who have taken the exam can check and download the answer key, response sheet, and question paper from the official website. They can also challenge the answer key by paying a non-refundable charge of Rs 200 for each question.

Key Points:

• Last Date for Objection Submission: August 11, 2024, at 11:50 PM
• Fee for Challenge: Rs 200 per question
• Website: csirnet.nta.ac.in

How to Raise an Objection:

1. Visit the Official Website:

   • Go to csirnet.nta.ac.in.

2. Find the Answer Key Challenge Link:

   • Click on the link labeled “Joint CSIR-UGC NET JULY-2024: Click here to Answer Key Challenge”.

3. Login:

   • Enter your login credentials including your application number and date of birth.

4. Select the Answer Key:

   • Choose the CSIR UGC NET answer key from the available options.

5. View and Challenge the Answer Key:

   • Click “View Question Paper” to see the question paper and answers. Use the “Click to view/Challenge Answer Key” link to submit your challenge.

6. Submit Your Objection:

   • Check the boxes next to the questions you want to contest, attach valid proof, and submit your objections.

7. Payment:

   • Pay the required fee for each challenge and save a copy of the submission form for your records.

Important Information:

• Review and Update: If any challenges are upheld, the answer key will be updated, and all candidates’ responses will be modified accordingly.
• Final Decision: The decision of the exam subject experts will be final, and no updates on the status of individual challenges will be provided by the NTA.

Exam Details:

• Dates: July 25, 26, and 27, 2024
• Shifts: Two shifts per day – 9 AM to 12 Noon and 3 PM to 6 PM
• Candidates: 2,25,335 students
• Exam Mode: Computer Based Test (CBT)